rdlc data matrix

rdlc data matrix

rdlc data matrix

rdlc data matrix

rdlc data matrix

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rdlc data matrix,
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rdlc data matrix,
rdlc data matrix,
rdlc data matrix,

rdlc data matrix,
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rdlc data matrix,
rdlc data matrix,
rdlc data matrix,
rdlc data matrix,

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First, passing by value is expensive for larger objects Primitive types and value types are generally small, and the overhead of passing by value is not large, so value types are usually passed by value, like this: void f(V v); Figure 4-3 shows the typical case of value types and reference types being passed to functions Because the local data is freed up when the function exists, any changes to the local data, either the local value type or the local handle, are not reflected outside the function A copy is created of a value type passed to a function, in this case declared as f(V v_local), and a value passed in with the expression f(v) Figure 4-3 also shows a reference type that was passed to a function declared as g(R^ r_local) and a handle passed in with the expression g(r).

The other problem we examined in 6 revolved around the idea of using a special (extreme) value to avoid using a null. We had a genuine date column, but used the data 31 December 4000 to represent missing data. Again, range-based queries suffered because although the optimizer was doing the date-based arithmetic correctly, the standard formula was using a high value that was totally unrealistic. We had data from 1 January 2000 to 31 December 2004, and a predicate: where date_closed between to_date('01-Jan-2003','dd-mon-yyyy') and to_date('31-Dec-2003','dd-mon-yyyy') Clearly, we expect Oracle to work out that we want one-fifth of the data. However, Oracle sees a high value of 31 December 4000, and works out a selectivity of about 3/2000 because it uses the following formula: (31st Dec 2003 - 1st Jan 2003) / (31st Dec 4000 - 1st Jan 2000) + 2/1828 = 0.00159 But when we build a histogram of just 11 buckets chosen simply as two per year plus one spare, just to show you that sometimes a very small number of buckets will do the CBO suddenly got a very good answer for its selectivity, hence cardinality. Using the same technique to display the data in the histogram in graph-ready form, the entire histogram looks like this: BUCKET ---------1 2 3 4 5 6 7 8 9 10 11 LOW_VAL ----------01-Jan-2000 15-Jun-2000 28-Nov-2000 13-May-2001 27-Oct-2001 11-Apr-2002 24-Sep-2002 09-Mar-2003 23-Aug-2003 05-Feb-2004 20-Jul-2004 HIGH_VAL WIDTH HEIGHT ----------- ---------- ---------15-Jun-2000 166 100.0548 28-Nov-2000 166 100.0548 13-May-2001 166 100.0548 27-Oct-2001 167 99.4556 11-Apr-2002 166 100.0548 24-Sep-2002 166 100.0548 09-Mar-2003 166 100.0548 23-Aug-2003 167 99.4556 05-Feb-2004 166 100.0548 20-Jul-2004 166 100.0548 31-Dec-4000 729188 .0228

As you setup each e-mail account, you will notice a new icon appearing on your Home screen tied to that particular account. If you like having individual icons, you can leave them alone. However, since all of your e-mail goes into your main Messages icon, you can hide these icons to clean up your Home screen. Follow these steps to hide these extra icons. 1. 2. 3. Highlight the icon you want to hide. Press the Menu key. Select Hide.

If you check the SQL I have used for this table (script defaults.sql in the online code suite), you will find that the actual values stored in the histogram are the Julian equivalents of the dates, and I have used a to_date() function to display them. An approximate graphical representation of these numbers appears in the third part of Figure 7-3.

The local handle in g refers to the same object on the managed heap..

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